Question

Phosphorus pentachloride dissociates as follows, in a closed reaction vessel

$PCl_ {5}(g) \: {⇌} \: PCl_3(g) + Cl_2(g)$
★ If the total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl₅ is x, the partial pressure of PCl₃ will be : ​

Answer 1

Answer:

=( x/x+1 )×P

Explanation:

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Answer 2

Answer:

$⛄ \sf \blue{ANSWER} \red{♡}࿐⛄$

$\sf \: PCl_ {5}(g)\: {⇌} \: PCl_3 (g) + Cl_2(g) \\ \sf \: Total \: number \: of \: moles \: at \: equilibrium \: \\ \sf \: = (1 - x) + x + x \\ \sf = 1 + x \\ \sf \: P _{pCl_{3}} = ( \frac{x}{1 + x} ) \times P$