Question

Phosphorus pentachloride dissociates as follows, in a closed reaction vessel $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$. If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl₅ is x, the partial pressure of PCl₃ will be
(a) $(\frac{x}{x-1}) P$
(b) $(\frac{x}{1-x}) P$
(c) $(\frac{x}{x+1}) P$
(d) $(\frac{2x}{1-x}) P$

Answer 1

$<b>$
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$\mathbb{NICE...QUESTION}$

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Phosphorus pentachloride dissociates as follows, in a closed reaction vessel $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$. If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl₅ is x, the partial pressure of PCl₃ will be
(a) $(\frac{x}{x-1}) P$
(b) $(\frac{x}{1-x}) P$
(c) $(\frac{x}{x+1}) P$
(d) $(\frac{2x}{1-x}) P$

→ [B]


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Answer 2

$\huge\red{Answer}$

(b) $(\frac{x}{1-x}) P$

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