Phosphorus react Cl2 to produce PCl3 according to reaction-
P4 + 6Cl2---> 4PCl3
If the density of PCl3 is 1.2g/cc.
How many kg of phosphorus is needed to produce 13.75 litres of PCl3?
Answers
Answered by
11
Answer:
Mass of PCl3
= 13.75 × 1000 × 1.2 g
= 13750 × 1.2 g
= 16500 g = 16.5 Kg
Moles of PCl3
= 16.5 ÷ (31+35.5×3) ×1000 mol
= 16500 ÷ 137.5 mol
= 120 moles
According to Reaction,
4 moles of PCl3 is produced by 1 mole of P4
Thus,
No. of moles of P4 req.
= 120 ÷ 4 = 30 moles
Mass of Phosphorus req.
= 30×31×4 ÷1000 Kg
= 3.72 Kg
Answered by
4
Answer:
Answer:
Mass of PCl3
= 13.75 × 1000 × 1.2 g
= 13750 × 1.2 g
= 16500 g = 16.5 Kg
Moles of PCl3
= 16.5 ÷ (31+35.5×3) ×1000 mol
= 16500 ÷ 137.5 mol
= 120 moles
According to Reaction,
4 moles of PCl3 is produced by 1 mole of P4
Thus,
No. of moles of P4 req.
= 120 ÷ 4 = 30 moles
Mass of Phosphorus req.
= 30×31×4 ÷1000 Kg
= 3.72 Kg
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