photocell connected in an electrical circuit is placed at a distance D from a source of light as a result current I flows in the circuit what will be the current in the circuit when the distance is reduced to D/2
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Answer:
9I ...not sure
Explanation:
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Given :
Distance between photocell and the source = D/2
To find :
The current flowing in the circuit = ?
Solution :
- The current flowing in the circuit due to photo electric source is given by
i = P/4πr2
- In the first case distance is D
i =P/4πD²
- In the second case distance id D/2
i₁=P/4π(D/2)²
i₁=4P / 4πD²
i₁=4i
The current flowing in the circuit becomes 4 times the initial current
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