photochemical decomposition of HI show that -d[HI]/dt=2Ia
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Reaction----->
2HI-----> H2 + I2
-1/2d(HI)/dt = d(H2)/dt = d(I2)/dt
I.e rate of decomposition of HI= rate of formation of H2=rate of formation of I2
2HI-----> H2 + I2
-1/2d(HI)/dt = d(H2)/dt = d(I2)/dt
I.e rate of decomposition of HI= rate of formation of H2=rate of formation of I2
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