Chemistry, asked by ishamehra461, 26 days ago

photoelectric emission is observed from a metal surface for the frequencies v1 and v2 radiation. if the maximum kinetic energy of the two electrons are in the ratio 1:2 then how is threshold frequency expressed

Answers

Answered by llchummill
1

Answer:

hv

1

=hv

0

+

2

1

mu

1

2

..(1)

hv

2

=hv

0

+

2

1

mu

2

2

.(2)

2

1

mu

1

2

=(

k

1

)

2

1

mu

2

2

From equation (1)-

hv

1

=hv

0

+

2k

1

mu

2

2

3)

2

1

mu

2

2

=khv

1

−khv

0

(4)

From equations (2) and (4), we get-

hv

2

=hv

0

−khv

0

+khv

1

v

0

(1−k)=v

2

−kv

1

v

0

=

(k−1)

kv

1

−v

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