Photoelectrons are removed with kinetic energy 1.864×10^-21 J, when photons of light with energy 4.23×10^-19 J fall on the metal. What is the minimum energy required per mole to remove an electron from potassium metal?
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rushi101:
in chemistry
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I assume that you're asking about the energy required to remove one mole of electron from the surface, and I also assume that the given kinetic energy is the maximum kinetic energy of the photoelectron. Moving on to solving the problem, (there's an error in the data, the work function of K is around 1.4 ×10^-19J per electron.
Ke= hf - ф
Ф=hf - K
=4.23×10^-19 - 1.864×10^-21
=4.21× 10^-19 J
Energy per mole,
W ×N
=4.21×10^-19 × 6.023×10^23
=25.36×10^4J
=~ 254 KJ
Ke= hf - ф
Ф=hf - K
=4.23×10^-19 - 1.864×10^-21
=4.21× 10^-19 J
Energy per mole,
W ×N
=4.21×10^-19 × 6.023×10^23
=25.36×10^4J
=~ 254 KJ
4.23×10^-19 _1.864×10^-21 iska ansr kya ayga agr hm subract krenge to...
4.21*10^-19 j
ohk
thkww
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Heya Frnd ,
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