Question

Photon of 5.5 electron volt energy falls on the surface of the better limiting photoelectron of maximum kinetic energy 4.0 electron volt stopping voltage required for these electrons are

Answer 1

Given :

Maximum kinetic energy of electron , $K.E=4\ eV$.

To Find :

The stopping voltage of these electron .

Solution :

We know , maximum kinetic energy is given by :

$K.E_{min}=eV_o$

Here , $V_o$ is the stopping voltage .

Therefore ,

$4\ eV=eV_o\\\\V_o=4\ V$

Therefore , stopping voltage of electron is 4 V .

Learn More :

Photoelectric Effect

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