Photon of energy 20 KeV is
Answers
Answered by
0
Answer:
E=hv=
λ
hc
λ=
E
hc
=
mv
h
=
p
h
momentum=p=
c
E
But E=20 eV =20×1.6×10
−19
J =32×10
−19
J
p=
3×10
8
32×10
−19
=10.66×10
−27
Kg m sec
−1
Hence, the correct option is A
Answered by
1
10.66×10
−27
Kg m sec
−1
E=hv=
λ
hc
λ=
E
hc
=
mv
h
=
p
h
momentum=p=
c
E
But E=20 eV =20×1.6×10
−19
J =32×10
−19
J
p=
3×10
8
32×10
−19
=10.66×10
−27
Kg m sec
−1
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