Physics, asked by shantuhargode, 2 months ago

photon of initial energy 90keV undergoes compton scattering at angle 60degree find 1) the energy of the scattered photon and 2) the recoil energy of the electron?​

Answers

Answered by aryanmeshram252003
2

Answer:

photon of initial energy 90keV undergoes compton scattering at angle 60degree find 1) the energy of the scattered photon and 2) the recoil energy of the electron?

Answered by ishwaryam062001
0

Answer:

Energy of scattered = 44.79 keV

E_recoil = 45.21 keV

Explanation:

From the above question,

They have given :

The photon of initial energy 90keV undergoes compton scattering at angle 60degree.

Here we need to find,

1) The energy of the scattered photon and

2) The recoil energy of the electron

To calculate the scattered photon energy using the Compton scattering equation: E_scattered = (hc/λ)(1 - cosθ), where θ is the scattering angle (60 degrees in this case).

Energy of scattered = (hc/λ)(1 - cos60)

Energy of scattered = (6.626x10^-34 x 3x10^8/0.001239)(1 - cos60)

Energy of scattered = 44.79 keV

To calculate the recoil energy of the electron using the conservation of energy:

Energy of recoil = Energy of initial - Energy of scattered.

Energy of recoil = 90keV - 44.79keV

E_recoil = 45.21 keV

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