photon of initial energy 90keV undergoes compton scattering at angle 60degree find 1) the energy of the scattered photon and 2) the recoil energy of the electron?
Answers
Answer:
photon of initial energy 90keV undergoes compton scattering at angle 60degree find 1) the energy of the scattered photon and 2) the recoil energy of the electron?
Answer:
Energy of scattered = 44.79 keV
E_recoil = 45.21 keV
Explanation:
From the above question,
They have given :
The photon of initial energy 90keV undergoes compton scattering at angle 60degree.
Here we need to find,
1) The energy of the scattered photon and
2) The recoil energy of the electron
To calculate the scattered photon energy using the Compton scattering equation: E_scattered = (hc/λ)(1 - cosθ), where θ is the scattering angle (60 degrees in this case).
Energy of scattered = (hc/λ)(1 - cos60)
Energy of scattered = (6.626x10^-34 x 3x10^8/0.001239)(1 - cos60)
Energy of scattered = 44.79 keV
To calculate the recoil energy of the electron using the conservation of energy:
Energy of recoil = Energy of initial - Energy of scattered.
Energy of recoil = 90keV - 44.79keV
E_recoil = 45.21 keV
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