Chemistry, asked by lokeshchinthakani, 10 months ago

Photons of energy 6eV are incident on a
potassium surface of work function 2. lev. What
is the stopping potential?
(A) -6V
(B) -2.1V
(C) -3.9V
(0) -8.1V

Answers

Answered by suryanshipathak

0

Answer:

(C) 3.9

Explanation:

ev°=E-¢

ev°= (6-2.1) eV

v°= 3.9 V

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