Question

Photons of equal energy were incident on two different
gas samples. One sample containing H-atoms in the
ground state and the other sample containing H-atorns
in some excited state with a principal quantum number
'n'. The photonic beams totally ionise the H-atoms. If the
difference in the kinetic energy of the ejected electrons in
the two different cases is 12.75 eV. Then find the principal
quantum number 'n' of the excited state.
Correct Explanation ❤❤​

Answer 1

$\huge\color{red}\mathfrak{n=3 }$

Answer 2

Answer:

Explanation:you have to do equate both kinetic energy.