Question

physic answers with steps plz

Answer 1

$\textbf { !! Hey Mate !! }$

$\textbf { your answer is }$

Given, the two forces is 2F & √2F
and it's resultant is F√10.

Let, angle between them is 'a'
therefore,

√(2F)^2 + (√2F)^2 + 2×2F×√2Fcosa =F√10

=> 4F^2 + 2F^2 + 4√2F^2cosa= 10F^2

=> F^2 ( 4 + 2 +4√2 cosa) = 10F^2

=> 6+4√2 cosa = 10

=> 4√2 cosa = 4

=> √2 cosa = 1

=> cosa = 1/√2

=> cosa = cos45° [ cos45° = 1/√2 ]

=> a = 45°

hence, angle between two forces is 45°

$\textbf { HOPE IT HELP YOU }$

Answer 2

Answer:

what is the answer tell me