physic:
Derive the eq Cp - Cv = R without taking value of Cv as 3RT and Cp as 5RT.
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Answer:
The specific heat capacity at constant pressure,
Cp=ΔQ/ΔT
Similarly, Cv=ΔU/ΔT
The work done against external pressure ΔW=P.ΔV
Using First Law of Thermodynamics,
ΔQ=Δu+ΔW
Cp.ΔT=Cv.ΔT+P.ΔV
From ideal gas equation,
P.ΔV=R.ΔT
Therefore,
Cp.ΔT=Cv.ΔT+R.ΔT (Cancelling ΔT)
Cp=Cv+R
Therefore, Cp-Cv=R . This is Mayer's Relation
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