Question

Physical interpretation of the relative displacement tensor?

Answer 1

I've resolved a relative displacement tensor into a strain tensor and a rotation tensor, where

the strain tensor is:

εi,j=⎛⎝⎜0.20000.80.400.40.4⎞⎠⎟εi,j=(0.20000.80.400.40.4)

and the rotation tensor is:

ωi,j=⎛⎝⎜000000.20−0.20⎞⎠⎟ωi,j=(00000−0.200.20)

How would these conditions physically change a small cube (with respect to the Cartesian cooridates (x,y,z)

Answer 2

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✔️✔️Physical interpretation of the relative displacement tensor

εi,j=⎛⎝⎜0.20000.80.400.40.4⎞⎠⎟εi,j=(0.20000.80.400.40.4)

Or


the rotation tensor is:

ωi,j=⎛⎝⎜000000.20−0.20⎞⎠⎟ωi,j=(00000−0.200.20)


How would these conditions physically change a small cube (with respect to the Cartesian cooridates


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