Question

physics 11th std......​

Answer 1

Answer:

Power = 1380 watts

Energy = 24,840 kilo joules

Explanation:

Given :

• Current taken by the electric heater = I = 6 Amperes

• Potential difference between the terminals of the heater = v = 230 volts

• Time taken = t = 5 hours = 18,000 seconds

To find :

• Power of the heater and energy consumed

V=I×R

230=6×R

R=230/6

Power = V×I

Power = 230×6

Power = 1380 watts

Energy = I²RT

Energy = 6²×230/6×18,000

Energy = 1380×18,000

Energy = 24,840,000 joules

1000 joules = 1 kilo joule

Energy = 24,840 kilojoules

The energy consumed is 24,840 kilojoules