Question

physics. 500.0ml of a gas is collected at 745.0mm Hg. what will the volume be at standard pressure?​

Answer 1

Answer:

Explanation:

P

1

V

1

=

P

2

V

2

. This form is useful in that we do not have to convert volume and pressure to standard forms. We can even use the non-standard pressure measurement of

m

m

H

g

.

1

a

t

m

=

760

m

m

H

g

. So the volume of your gas should slightly reduce:

V

2

=

P

1

×

V

1

P

2

=

745

⋅

m

m

⋅

H

g

×

500.0

⋅

m

L

760

⋅

m

m

⋅

H

g

=

?

?

m

L

.

Explanation:

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Answer 2

Answer:

This is an application of Boyle's law:

P₁V₁ = P₂V₂. we don't have to convert volume and pressure to standard forms. we can even use the pressure with mmHg

1 atm = 760 mmHg

V₂ = P₁V₁ / P₂ = 745 x 500 / 760 = 490 ml

Note that here we assume constant temperature.......☺

Explanation:

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