Question

physics. 500.0ml of a gas is collected at 745.0mm Hg. what will the volume be at standard pressure?​

Answer 1

Answer:

Explanation:

P

1

V

1

=

P

2

V

2

. This form is useful in that we do not have to convert volume and pressure to standard forms. We can even use the non-standard pressure measurement of

m

m

H

g

.

1

a

t

m

=

760

m

m

H

g

. So the volume of your gas should slightly reduce:

V

2

=

P

1

×

V

1

P

2

=

745

⋅

m

m

⋅

H

g

×

500.0

⋅

m

L

760

⋅

m

m

⋅

H

g

=

?

?

m

L

.

Answer 2

$\huge\red{\underline{{\boxed{\textbf{QUESTION}}}}}$

500.0ml of a gas is collected at 745.0mm Hg. what will the volume be at standard pressure?

$\huge\red{\underline{{\boxed{\textbf{ANSWER}}}}}$

According to the question :-

T is constant

p1V1 = p2V2 ( Boyle's law)

Standard pressure = 1 atm => 760 mm Hg

745 x 500 = 760 V2

V2 = 510 mL

@HarshPratapSingh