Question

Physics
A body starts from the rest and move along the X axis with constant acceleration 5ms-²for 8 seconds.if it then continues with constant velocity, what distance will the body cover in 12 seconds since it started from the rest

Answer 1

Answer:

starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds. If it then continues with constant velocity what distance will the car cover in 12 seconds since it started from rest? s = v × t = 40 × 4 = 160 m .

explanation

initial velocity u = 0

Acceleration, (a) = 5 ms-2 and time (t) = 8 s

From first equation of motion,

v = u + at

On putting a = 5 ms-2and t = 8 s in above equation, we get

v = 0+ 5×8= 40ms’1

So, final velocity v is 40 ms’1.

Again, from second equation of motion,

So, the distance covered in 8 s is 160 m. -­

Given, total time t = 12 s.

After 8 s, the car continues with constant velocity i.e., the car will move with a velocity of 40 ms-1.

So, remaining time t’= 12 s-8 s= 4s

The distance covered in the last 4s (s’) =Velocity x Time [∴ Distance = Velocity x Time]

= 40 x 4 = 160 m

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