Question

[Physics]

A bulb is connected to a battery of p.d. 4V and internal resistance 2.5 ohm. A steady current of 0.5 A flows through the circuit. Calculate :

(1) the total energy supplied by the battery in 10 minutes
(ii) the resistance of the bulb
(iii) the energy dissipated in the bulb in 10 minutes.

Ans. (i) 1200 J (ii) 5.5 ohm (iii) 825 J

_
•Kindly don't forget to match your answer with the answer given in the Question
• HIGH-QUALITY ANSWERS!!​

Answer 1

Required Answer :-

1]

$\sf Energy = \dfrac{V^2 \times T}{R}$

Where

V = Potential Difference

T = Time

R = Resistance

For resistance

$\sf V = IR$

$\sf 4 = 0.5 \times R$

$\sf \dfrac{4}{0.5} = R$

$\sf 8 \Omega = R$

Now

Energy consumed

$\sf E = \dfrac{(4)^2 \times 600}{8}$

$\sf E = \dfrac{16 \times 600}{8}$

$\sf E = 2 \times 600$

$\sf E = 1200 J$

2]

$\sf Resistance_{(bulb)} = Resistance_{(total)} - Resistance_{(battery)}$

$\sf Resistance_{(Bulb)} = 8 \Omega - 2.5 \Omega$

$\sf Resistance_{(Bulb)} = 5.5 \Omega$

3]

For the energy dissipated

$\sf E_{I} = I^2Rt$

$\sf E_I = (0.5)^2 \times 5.5 \times 600$

$\sf E_I = 0.25 \times 5.5\times 600$

$\sf E_I = 825 \; Joule$

Note - Kindly watch the answer from web

Answer 2

Given :-

• A bulb is connected to a battery whose potential difference is 4V

• Internal resistance = 2.5 ohm

• Steady current = 0.5A

Solutions :-

1) Here, we have to find the energy supplied by a battery in 10 minutes

Therefore,

As we know that,

Energy = Power * Time

Energy = VI * T. [ P = VI ]

Subsitute the required values,

E = 4 * 0.5 * 10min

[ SI unit of time is seconds, so convert minutes into seconds ]

E = 4 * 0.5 * 10 * 60

E = 4 * 0.5 * 600

E = 2400 * 0.5

E = 1200 J

Hence, The energy supplied by a battery in 10 minutes is 1200 J .

2) Here, we have to find the resistance of the bulb .

Internal resistance (r) = 2.5 ohm

Potential difference ( V) = 4V

Steady current ( I) = 0.5A

Resistance of the bulb ( R) = ?

Now,

We know that,

V = RI

Therefore,

V = ( r + R ) * I

V/I = r + R

R = V/I - r

Subsitute the required values,

R = 4/0.5 - 2.5

R = 4 - 1.25 / 0.5

R = 2.75/0.5

R = 5.5 ohm

Hence, The resistance of the bulb is 5.5ohm

3) Here, we have to find the energy dissipated in the bulb in 10 minutes

[ Dissipation of electric energy means wastage of electrical energy ]

Therefore,

By using joule law of heating that is ,

H = I^2Rt

Subsitute the required values,

H = 0.5 * 0.5 * 5.5 * 600

H = 0.25 * 5.5 * 600

H = 1.375 * 600

H = 825 J

Hence, The energy dissipated in the bulb in 10 minutes is 825 J $.$