physics a level ques help explain in detail plz thx
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Imagine a beaker containing the liquid and a vertical straw (not an inclined straw).
Atmospheric pressure p0 acts on the surface of the liquid.
Now, the child is sucking at top of the straw with a pressure of 0.9p0 (since the child is capable of lowering the pressure at the top of the straw by 10%). As the child sucks up the liquid rises up the straw of length h.
The difference in pressure at the surface of the liquid in the beaker (= p0) and the pressure at the top of the straw (= 0.9p0) is represented by the pressure due to the column of liquid in the straw (= hρg).
p0 – 0.9p0 = hρg
hρg = 0.1p0 = p0 / 10
Length of straw, h = p0 / 10ρg
Atmospheric pressure p0 acts on the surface of the liquid.
Now, the child is sucking at top of the straw with a pressure of 0.9p0 (since the child is capable of lowering the pressure at the top of the straw by 10%). As the child sucks up the liquid rises up the straw of length h.
The difference in pressure at the surface of the liquid in the beaker (= p0) and the pressure at the top of the straw (= 0.9p0) is represented by the pressure due to the column of liquid in the straw (= hρg).
p0 – 0.9p0 = hρg
hρg = 0.1p0 = p0 / 10
Length of straw, h = p0 / 10ρg
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