Question

◆ PHYSICS AHEAD ◆

What is the amount of heat to be supplied to make 10 gram of ice at 0℃ to water at 10℃ [Given : latent heat of fusion of ice is 80cal/g.]

Answer 1

hiiii mate here your answer ✔️ ✔️
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Okay.

So firstly you need to convert ice (solid state) to water (liquid state), for which you need to supply Latent Heat of Fusion for ice.

The Latent Heat of Fusion for ice is 384J/gram.

So 10 grams of ice require:

10X384 = 3840J of energy.

Next we need to raise the temperature of this water from 0°C to 20°C.

The specific heat capacity of water is:

4.184J/g/°C.

So 10g water from 0°C to 20°C require:

10X20X4.184 = 836.8J

Total energy required

= 3840 + 836.9

= 4676.9J

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Answer 2

HEYA,

Here is your answer

we have to use two formulas- Q=M*S*CHANGE IN TEMEPERATURE-this when the state is same
​                                               
Then energy required to reach temp. 100 degrees Celsius we have to use 
energy required =mass*specific heat*delta t
=10*1/2*100
as specific heat of water is .5
so it will become 5*100
so the temperature needed to reach 100 degrees celsius is 500 calories
then we have to use  the formula energy required=mass*latent heat
so=10*540
latent heat of water vapour is 540 calories
we will get 5400
then we have to add the two solutions.
so, 5400+500
=5900 calories are required.