Question

#PHYSICS

Answer the question in the attachment.

#Spammed answer will be deleted on the spot.​

Answer 1

Answer:

$\displaystyle{\dfrac{C_1}{C_2}=\dfrac{5}{3}}$

Explanation:

Since , no current flow through capacitor .

Then , Potential   V = I R

So ,  Potential across C₁ = 2 × I + 4 × I = 6 I

Potential across C₂ = 4 × I + 6 × I = 10 I

We know Capacitance = Charge / Potential

C = q / V

q = C V

Given charge is same in C₁ and C₂ :

V₁ C₁ = V₂ C₂

Putting values here

( 6 I ) C₁  = ( 10 I ) C₂

$\displaystyle{\dfrac{C_1}{C_2}=\dfrac{10 \ I}{6 \ I}}\\\\\\\displaystyle{\dfrac{C_1}{C_2}=\dfrac{5}{3}}$

Thus , we get answer .

Answer 2

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

$\sf Option => 4\\\\\dfrac{C_1}{C_2} = \dfrac{5}{3}$

$\mathfrak{\large{\underline{\underline{Explanation:-}}}}$

Here, No current flow through capacitor.

So, We have to find Potential.

We know that :

Potential :

★ $\boxed{\sf V= I R}}$

Potential across of C₁ :

=> 2 × I + 4 × I = 6 I

Potential across C₂ :

=> 4 × I + 6 × I = 10 I

We also know that :

★ $\boxed{\sf{Capacitance = \dfrac{Charge}{Potential}}}$

=> C = q\V

=> q = C V  

Given that :

V₁ C₁ = V₂ C₂

(6 I) C₁  = (10 I) C₂

Put the given Values :

$\sf{\implies \dfrac{C_1}{C_2}=\dfrac{10 \ I}{6 \ I}}\\\\\\\sf{\implies \dfrac{C_1}{C_2}=\dfrac{5}{3}}$

Hence,

The Option => 4 is Correct!