Question

#physics answer with clear.explanation​

Answer 1

$resolving \: limit \ alpha = \frac{1.22 ×lambada}{d} \\ \frac{1.22 \times 500 \times {10}^{ - 9} }{5 \times {10}^{ - 3} } \\ = 122 \times {10}^{ - 6}$

from above attachment

$\alpha = \frac{d}{400}$

$d = 400 \times \alpha$

$d = 400 \times 122 \times {10}^{ - 6} \\ = 48800 \times {10}^{ - 6} \\ = 48.8 \times {10}^{ - 3} \\ = 48.8m$

≈ 50 m

therefore your option should be (C)

Hope it will be helpful✌

Answer 2

Answer:

meow.. I think already this part completed for ur exam but still I am sending as we r preparing for NEET

hope it helps you