Question

Physics assignment:

(1) Derive a relation for the electric potential at a certain point due to a point charge.

(2) Derive an expression for capacitance of a parallel plate capacitors.

(3) Derive an expression for Energy stored by the Capacitor.

Answer 1

Answer:

PLZ MARK AS BRAINLIEST

❀(*´▽`*)❀

Answer 2

Answer:

• 1.Electric potential of a point charge is V=kQ/r V = k Q / r . Electric potential is a scalar, and electric field is a vector. Addition of voltages as numbers gives the voltage due to a combination of point charges, whereas addition of individual fields as vectors gives the total electric field.
• ANSWER
• Let the two plates are kept parallel to each other separated be a distance d and cross-sectional area of each plate is A.
• Electric field by a single thin plate E
• ′
• =
• 2ϵ
• o
• σ
• Total electric field between the plates E=
• 2ϵ
• o
• σ
• +
• 2ϵ
• o
• σ
• Or E=
• ϵ
• o
• σ
• Or E=
• Aϵ
• o
• Q
• Potential difference between the plates V=Ed
• ⟹ V=
• Aϵ
• o
• Qd
• Capacitance C=
• V
• Q
• Thus we get capacitance of parallel plate capacitor C=
• d
• Aϵ
• o
• solution
• The energy stored in a capacitor can be expressed in three ways: Ecap=QV2=CV22=Q22C E cap = QV 2 = CV 2 2 = Q 2 2 C , where Q is the charge, V is the voltage, and C is the capacitance of the capacitor. The energy is in joules when the charge is in coulombs, voltage is in volts, and capacitance is in farads