physics class 11 science
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Answered by
5
HEY frnd here is ur ans.....
GIVEN:
Initial velocity (u) = 20km/h
final velocity (v) = 0
Distance (s) = 2km
speed of bird = 60 km/h
by using formula :
v^2 = u^2 +2as
by putting the values...
0 = (20)^2 + 2×a×2
0 = 400 + 4a
4a = -400
a = -400/4 = - 100km/h^2
Now,,
time taken to travel 2km to reach platform
v = u + at
by putting the value
0 = 20 - 100t
t = 1/5 hr
Now,
Distance travel in 1/5 hr.
Distance = speed × time
Distance = 60 × 1/5 =12 km .... Ans. ;)
Hope it helps you✌✌
Thankyou ☺
SWEETY ⚡⚡
GIVEN:
Initial velocity (u) = 20km/h
final velocity (v) = 0
Distance (s) = 2km
speed of bird = 60 km/h
by using formula :
v^2 = u^2 +2as
by putting the values...
0 = (20)^2 + 2×a×2
0 = 400 + 4a
4a = -400
a = -400/4 = - 100km/h^2
Now,,
time taken to travel 2km to reach platform
v = u + at
by putting the value
0 = 20 - 100t
t = 1/5 hr
Now,
Distance travel in 1/5 hr.
Distance = speed × time
Distance = 60 × 1/5 =12 km .... Ans. ;)
Hope it helps you✌✌
Thankyou ☺
SWEETY ⚡⚡
ManjeetGupta:
thanku
Answered by
41
Final velocity 'v' is 0 because it is assumed that the train is supposed to stop when it reaches the pole.
initial velocity = 20 km/hr ...(given)
s = 2 km, the distance of the train from the pole.
Now,
Distance = speed (of bird) x time (above calculated)
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