physics class 9 icse motion in one dimension
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(i) max.velocity reached is=u+at=0+2×10=20m/s
(i)retardation in last 50 s is = 2/5m/s^2.
(iii) total distance travelled is=(100+4000+500)m=4600m.
(iv)average velocity=4600/260=17.6m/or18m/s approx.
(i)retardation in last 50 s is = 2/5m/s^2.
(iii) total distance travelled is=(100+4000+500)m=4600m.
(iv)average velocity=4600/260=17.6m/or18m/s approx.
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