Physics class 9 motion numerical
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Question 1
A train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance travelled by car.
Answer a. Acceleration is given by
a
=
Δ
v
Δ
t
Δ
v
=
54
−
36
=
18
k
m
/
h
r
=
5
m
/
s
So a=.5 m/s2
b. Distance is given by
S
=
u
t
+
1
2
a
t
2
So s=125m
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