PHYSICS CLASS IX CBSE
FORCE AND LAWS OF MOTION
PLZ ANSWER
A 150 gram ball travelling at 30 m/s strikes the palm of player's hand and is stopped in 0.06s. Calculate the force exerted by the ball on the hand.
Answers
Answered by
6
m=150g=0 15kg
u=30m/s
v=0
F=(?)
F=m.a
F=m.(v-u)/t
F= 0.15×{(0-30)/0.06}
F=-75N
please mark as brainlist answer
u=30m/s
v=0
F=(?)
F=m.a
F=m.(v-u)/t
F= 0.15×{(0-30)/0.06}
F=-75N
please mark as brainlist answer
Answered by
2
ist calculate acceleration, let the initial speed be u and final speed is given 30m/s we know that
a =dv/dt Means acclereration =30/0.06 acceleration comes out to be 500m/s^2 we know that force =mass ×acceleration , F= 0.15×500 , 75 NEWTON is correct ans
a =dv/dt Means acclereration =30/0.06 acceleration comes out to be 500m/s^2 we know that force =mass ×acceleration , F= 0.15×500 , 75 NEWTON is correct ans
mitajoshi11051976:
noy 75 but -75N
sorry I for get it
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