Question

physics eq plz ans fast​

Answer 1

Given:

Potential difference (V) = 100 V

Time (t) = 6 minutes and 58 seconds = 418 seconds

Current (I) = 0.2 A

To Find:

Heat produced (H)

Answer:

Heat produced in a circuit:

$\boxed{ \bf{H = VIt}}$

By substituting values we get:

$\rm \implies H = 100 \times 418 \times 0.2 \\ \\ \rm \implies H = 8360 \: J$

$\bf 1 J = \dfrac{1}{4.18} \ cal :$

$\rm \implies H = \dfrac{8360}{4.18} \: cal \\ \\ \rm \implies H = 2000 \: cal \\ \\ \rm \implies H = 2 \: kcal$

$\therefore$ $\boxed{\mathfrak{Heat \ produced \ (H) = 2 \ kcal}}$

Answer 2

Steps to solve:

• As per in the question it is given that potential difference is 100V that is applied for 6 minutes and 58s ( t = 6 minutes and 58s) and the current ( I ) flowing through it is 0.2 Ampere

• So here, we can apply the formula || H = VIt || to find the heat produced.

• And then we'll convert the result in calories.

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Solution:

$\large \tt {Given-}$

• $\tt { Potential \: difference (V) = 100V}$

• $\tt { Current \: flowing( I) = 0.2A}$

• $\tt { time (t) = 6\: minutes \: 58 s }$

Converting to its standard form-

$\leadsto \tt { 6 \: minutes \: 58 s}$

$\leadsto \tt { (6 \times 60 + 58) s}$

$\leadsto \tt { (360 + 58) s}$

$\leadsto \tt { 418 s}$

$\large \tt {To \: find-}$

• $\tt { Heat \: produced \: in \: calories ( H)}$

$\large \tt {Calculation-}$

We know that,

• $\large \rm \orange { H = VIt}$

Therefore,

$\tt \purple { \implies H = 100 \times 0.2 \times 418}$

$\tt \purple { \implies H = 41800 \times 0.2}$

$\tt \purple { \implies H = 8,360 J}$

Now converting joule to calories-

We know that,

• $\large \rm \orange { 1 J = \dfrac{1}{4.18}calories}$

Therefore,

$\tt \purple { H = 8,360J = \dfrac{8,360}{4.18}cal}$

$\tt \purple { H = 8,360J = (\dfrac{8,360}{418}\times 100)cal}$

$\tt \purple { H = 8,360J = (\dfrac{8,360}{418}\times 100)cal}$

$\tt \purple { H = 8,360J = \cancel {\dfrac{8,36,000}{418}} = 2000cal.}$

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Some formulae:

If current ( I ), resistance ( R ) and time are given then,

• $\large \rm \orange { H = {I} ^{2} RT}$

If potential difference ( V ), time ( t ) and R ( resistance ) are given then,

• $\large \rm \orange { H = \dfrac{{V} ^{2} t}{R} }$

If potential difference ( V ), time ( t ) and current ( I ) are given then,

• $\large \rm \orange { H = VIt}$

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