Question

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A baseball is popped straight up into the air and has a hang time of 6 second. Determine the maximum height to which the ball rises?​

Answer 1

Answer:

distance=180 m

Explanation:

v= u+at

v= 0

a= -10m/s^2

-u= at

-u=-10 x3 =30m/s

s=ut + 1/2 at^2

=30 x 3 -10 x 3 x3/2

=90-90/2

=90-45distance

=45m

Answer 2

Explanation:

Time=6/2=3s

gravity=-9.8

v=u+at

0 =u+(-9.8)(3)

29.4=u

v²-u²= 2gh

0 -(29.4)²= 2(-9.8)h

864.36=-19.6h

864.36/19.6=-h

44.1=-h

-44.1=h

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