Physics, asked by AsStHaPandeY, 11 months ago

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Question:A body moves from rest with a uniform accerelation and travels 270m in 3s.Find the velocity of the body at 10 sec after the start?

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Answers

Answered by Harshit1121z
2

Answer:

600 m/s

Explanation:

As body start from rest so its initial velocity is zero.

now it travels 270 m in 3 seconds, by using the equation

S = ut + 1/2 at^2

we get the value of acceleration = 60 m/s^2

now velocity at 10 seconds

using the equation, v = u + at

we get final velocity at 10 second = 600 m/s

Answered by astha23kz
0

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Answer:

here the main thing is uniform acceleration which means that "a" would be constant such that acceleration after 3s would be equal to acceleration after 10 s so from 1st case we will find the acceleration from 2nd equation of motion. i.e s=ut + 1/2 at^{2} from this equation we will find 

  1/2 at2 = s-ut 

  a= 2(s-ut)/t2

  here initial speed u=0 so ut = 0

  a= 2*270/3*3 

  a = 60m/s2 - (1)

 Now we know that v= u+at

from eqn 1 a= 60m/s2

 so here v= 0+ 60*10

 v=600m/s

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