Physics genius♥️
Question:A body moves from rest with a uniform accerelation and travels 270m in 3s.Find the velocity of the body at 10 sec after the start?
♥️Aastha.
Answers
Answer:
600 m/s
Explanation:
As body start from rest so its initial velocity is zero.
now it travels 270 m in 3 seconds, by using the equation
S = ut + 1/2 at^2
we get the value of acceleration = 60 m/s^2
now velocity at 10 seconds
using the equation, v = u + at
we get final velocity at 10 second = 600 m/s
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Answer:
here the main thing is uniform acceleration which means that "a" would be constant such that acceleration after 3s would be equal to acceleration after 10 s so from 1st case we will find the acceleration from 2nd equation of motion. i.e s=ut + 1/2 at^{2} from this equation we will find
1/2 at2 = s-ut
a= 2(s-ut)/t2
here initial speed u=0 so ut = 0
a= 2*270/3*3
a = 60m/s2 - (1)
Now we know that v= u+at
from eqn 1 a= 60m/s2
so here v= 0+ 60*10
v=600m/s
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