Physics Headache™ 1 : 20 points , 5 mins . Question 6
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P = (a-t²)/bx
Pressure = Force/Area
P = m×a/area
P = M×(L/T²) × (1/L²)
P = M¹ L¯¹ T ¯²
M¹ L¯¹ T¯² = (a- T²)/bL¹
a - T² = b M¹ Lº T¯²
a/b = M¹ Lº T¯²
========================
Pressure = Force/Area
P = m×a/area
P = M×(L/T²) × (1/L²)
P = M¹ L¯¹ T ¯²
M¹ L¯¹ T¯² = (a- T²)/bL¹
a - T² = b M¹ Lº T¯²
a/b = M¹ Lº T¯²
========================
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HELLO FRIENDS ,
We know that
Pressure = Force/area
(For dimension of pressure put value of dimensions of force and area)
Pressure = m. a / a (force = m.a)
= [M][L]-1[T]-2
NOW PUT it in main equation
M¹ L-¹ T-² = (a- T²)/bL¹
a - T² = b M¹ T-²
a/b =M¹ T-²
OR
a/b = M¹ Lº T-²
so option B) is correct
-----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
We know that
Pressure = Force/area
(For dimension of pressure put value of dimensions of force and area)
Pressure = m. a / a (force = m.a)
= [M][L]-1[T]-2
NOW PUT it in main equation
M¹ L-¹ T-² = (a- T²)/bL¹
a - T² = b M¹ T-²
a/b =M¹ T-²
OR
a/b = M¹ Lº T-²
so option B) is correct
-----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
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