Question

PHYSICS - IA
2. A block of mass 'm' is lying on a rough
10
G
5)
inclined having an inclination antan
The inclined plane is moving horizontally with
a constant acceleration of a = 2 ms as shown
in the figure. The maximum value of
coefficient of friction so that the block remains
stationary with respect to the inclined plane
is (Acceleration due to gravity = 10ms?)​

Answer 1

macosα+mgsinα=μN

N+masinα=mgcosα

N=[mgcosα−masinα]

macosα+mgsinα=μ[mgcosα−masinα]

[

gcosα−asinα

acosα+gsinα

]=μ⇒μ=[

g−atanα

a+gtanα

]=

12

5

hope it helps

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#mumukshu

Answer 2

Answer:

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