Question

physics. if a gas at 25. 0 c occupies 3.60liters at a pressure of 1.00atm,what will be it's volume at a pressure of 2.50atm ?​

Answer 1

Explanation:

If a gas at 25.0 atm occupies 3.60 liters at a pressure of 1.00 atm, what will be its volume at a pressure of 2.50 atm?

Given data:

V₁ (initial volume) = 3.60 liters             P₁ (initial pressure) =  1.00 atm

V₂ (final volume)  = ? unknown (atm)  P₂ (final pressure) = 2.50 atm

Solution:

In solving this problem, we can use the formula of

Boyle's law which is P₁V₁ = P₂V₂

                                             P₁V₁ = P₂V₂

                     1.00 atm ×  3.60 L = 2.50 atm ×  V₂

   1.00 atm ×  3.60 L / 2.50 atm =  V₂

              3.60  atm.L / 2.50 atm = V₂

                                           1.44 L = V₂

Answer:

The new volume at a pressure of 2.50 atm is = 1.44L

Answer 2

Given:

A gas at 25°C and 1.00 atm pressure occupies 3.60 L volume.

To Find:

The volume of the gas at the same temperature but 2.50 atm pressure.

Solution:

From Boyle's law, we know that pressure exerted by a gas at a constant temperature is inversely proportional to its volume.

⇒ $P_1V_1=P_2V_2$

Here, the initial pressure and volume given are $P_1=1.00atm$ , and $V_1=3.60L$ and final pressure is given as $P_2=2.50atm$.

Applying Boyle's law,

   $(1.00)*(3.60)=(2.50)*V_2$

⇒ $V_2=\frac{3.60}{2.50}$

⇒ $V_2=1.44L$

Hence, the volume of the gas at 2.50 atm pressure is equal to 1.44 Litres.