Physics
If the thickness of a conducting metal rod is halved, the amount of heat conducted by the rod will become......times provided other
parameters remaining constant.
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the amount of heat conducted by the rod will become 2 times provided other
it is given that, thickness of a conducting metal rod is halved.
we know, amount of heat conducted by the rod is , dQ/dt = KA dT/dx
where K is thermal conductivity, A is cross sectional area , dT is change in temperature and dx is thickness of conducting metal.
if K, A and dT remain constant.
then, dQ/dt ∝ 1/dx
I mean, heat conducted by the rod is inversely proportional to thickness of rod.
now, if the thickness of a conducting metal rod is halved then heat conducted by the rod will be twice.
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