Question

PHYSICS KINEMATICS

a car has a speed of +15 m/s relative to the ground. It passes a cyclist traveling in the same straight line. The speed of the car relative to the cyclist is +12 m/s. What's the speed of the cyclist relative to the ground?

Answer 1

The speed of the cyclist relative to the ground is +3 m/s.

Answer 2

Answer:

The speed of the cyclist relative to the ground=3 m/s

Explanation

Velocity of the car wrt to ground(V car-ground)= 15m/s.

Velocity of the car relative to the cyclist(V car-cyclist)= 12m/s.

so, the velocity of cyclist relative to the ground (V cyclist-ground)= V car-ground subtracted by V car-cyclist.

which equals to 15m/s-12m/s= 3m/s.

Here the concept of relative motion comes to play which is a type of motion being observed from a separate frame of reference. so for different frame of references the relative velocity will be different.