Question

Physics neet questions : car a standing 200m behind car b and both cars are initially at rest.both cars start moving forward at the same instant but with different accelerations.car b has an acceleration 2m/s and car a has an acceleration 4m/s.the car a will catch up with car b after a time of?

Answer 1

here by equation s,=ut + 1/2 at'2
200=1/2×2×t'2 here comes t=14.14 now car 2 simiarly by this equation t=10 than car a can catch the car withing 5 sec.