Physics numerical problems. A convex mirror form the image of an object placed at a distance of 40cm in the front of mirror at a distance of the 10cm find the focal length of the mirror
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DURGA39:
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here given that....image distance {(v) = 10cm
object distance {(u) =40cm
w.k.t 1/f =1/u -1/v
1/f = 1/40 -1/10
1/f= 13.3cmsquare
object distance {(u) =40cm
w.k.t 1/f =1/u -1/v
1/f = 1/40 -1/10
1/f= 13.3cmsquare
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