Question

Physics Numerical :-

starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6ms‐¹ in 30s. Then he applies brakes such that the velocity of the bicycle comes down to 4ms‐¹ in the next 5s. Calculate the acceleration of the bicycle in both the cases.

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Answer 1

$\huge\bold{Answer:-}$

In the first case :-

Initial velocity ( u ) = 0

Final velocity ( v ) = 6 ms‐¹

Time ( t ) = 30 s

$\huge\bold{a=v-u/t}$

substituting the given values of u, v and t :-

a = ( 6 ms‐¹ – 0 ms‐¹ ) / 30 s

a = 0.2 ms‐²

In the second case :-

Initial velocity ( u ) = 6 ms‐¹

Final velocity ( v ) = 4 ms‐¹

Time ( t ) = 5 s

Then, a = ( 4 ms‐¹ – 6 ms‐¹ ) / 5 s

a = – 0.4 ms‐²

The acceleration of the bicycle in the first case is 0.2 ms‐² and in the second case it is –0.4 ms‐².

Answer 2

Explanation:

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