Question

Physics
Numericale
A Train is traveling at a speed of 90 km lh
brechas ou apply so as to produce a uniform
acceleration of 0.5 m/s2o find How for the train
will go before it id or brought to Rest?
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Answer 1

Answer:

Explanation:

Correct Question,

A train is travelling at a speed of 90 km/h brakes are applied so as to produce a uniform acceleration of -0.5 m s-2 find how far the train will go before it is brought to rest?

Solution,

Here, we have

Initial speed of the train, u = 90 km/h = 90 × 5/18 = 25 m/s

The final speed of the train, v = 0

Acceleration = - 0.5 m/s²

To Find,

Distance acquired,s = ?

According to the 3rd equation of motion,

We know that,

v² = u² + 2 as

Putting all the value, we get

⇒ v² = u² + 2 as

⇒ (0)² = (25)² + 2 × (- 0.5) s

⇒ s = 625 m

Hence, The train will cover a distance of 625 m before coming to rest.

Answer 2

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✰Correct Question ✰

⋄ A Train is traveling at a speed of 90 km/h

and to produce a uniform acceleration of 0.5 m/s² find How far the train will go before it brought to Rest?

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✰Given :-

⋄ Initial velocity of train (u) = 90km/h=90 ×5 /18= 25m/s

⋄ Final velocity (v) =0m/s

⋄ Acceleration of train (a) = 0.5m/s²

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✰To Find :-

⋄ Distance covered by train (s)????

_______________________________

✰Solution :-

By using 3rd equation of motion

➧ v² = u² +2as

➧ 0² = 25² +2 × 0.5 ×s

➧ s= 625/1

➧ s= 625m.

∴The distance covered by train 625 m.