Question

#PHYSICS

Q. Find the value of self inductance for the given circuit in the attachment.

#Answer needed with steps and explanation.​

Answer 1

Answer:

So , this is a case of a circuit with Alternating Current.

In order to solve this type of questions, you need to be familiar with the following terms :

INDUCTIVE REACTANCE , IMPEDANCE, ETC.

You need to remember the relationship between Inductive reactance and frequency of alternating current.

The relationship is given by the formula:

XL = w * L,

where XL is the Inductive reactance,

w is omega ( related with frequency),

and L is the self inductance.

As per the question, Inductive reactance is given as 100 ohm, and frequency as

50 Hz.

Now refer to the above photo.

The final answer is (1/π) henry.

Answer 2

Answer:

The answer is $\sf \dfrac{1}{\pi}$

Explanation:

Given Data -

$\sf X_L = 100 \Omega$

$\sf R = 60\Omega$

$\sf X_C = 20\Omega$

$\sf\;200 V$

$\sf 50 Hz$

____[A Circuit with Alternating Current!]

Solving this type of Problems,

We took help from,

The relationship between Inductive reactance and frequency of alternating current.

Which can be written as -

$\bigstar\;\boxed{\sf XL =\;\omega \times L}}$

Here,

XL stands for Inductive reactance,.

ω stands for Omega.

L stands for self inductance.

According to the question,

$\sf\\ \\\implies X_L = (2\pi f) \time L\quad\quad [F = Frequency]\\ \\\implies 100 = 2\pi\times50\times\;L\\ \\\implies L = \dfrac{1}{\pi}$

Hence,

The answer is $\sf \dfrac{1}{\pi}$