Physics Question :-
A train moves from rest to a speed of 60 m/s in 20 seconds. What is the magnitude of its acceleration?
Answers
Answered by
0
Answer:
acceleration = 3m/s^2
Explanation:
Initial velocity ( u) = 0m/s
final velocity - 60 m/s
time (t) = 20s
acceleration (a) = ?
Formula"
v - u = at
60 - 0 = 20a
60 = 20a
a = 60- /20
a = 3m/s^2
Hope it helps u !!
Answered by
116
Required Solution :
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Initial velocity of train (u) = 0
Final velocity of train (v) = 60m/s
Time taken by train (T) = 20sec
- Acceleration of the train ?
- v = u + at
v = Final velocity
u = Initial velocity
a = acceleration
t = Time taken
- For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of train !
v = u + at
60m/s = 0 + a × 20s
60 = 0 + 20a
60 = 20a
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