Question

physics question, is my answer correct pls tell
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Answer 1

$2.01 \times {10}^{20} N$

Explanation:

$use \: \: formula \\ \boxed{ F_{em} = G \frac{m_{e}m_{m}}{ {r}^{2} } } \\ = \frac{(6.7 \times {10}^{ - 11}N {m}^{2} {kg}^{ - 2} ) \times (6 \times {10}^{24}kg) \times (7.4 \times {10}^{22}kg )}{ {(3.84 \times {10}^{5}m )}^{2} } \\ = \boxed{2.01 \times {10}^{20} N}$