physics question
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Explanation:
1) Acceleration at OA = Vf - Vi / Time taken
= 15 - 0 / 3
= 5m/s²
Similarly for BC we get,
Acceleration = 0 - 15/8 - 3 = -15/3 = -5m/s²
2) We know, Velocity= Displacement / Time
Therefore, Displacement at AB = 15 x (5-3)
= 30m
3) Here we see AB is parallel to the X-Axis (Time) with velocity at Y-Axis. So the velocity will be uniform at AB
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