Question

Physics question please verified answer. An object is placed at a distance of 10 cm from the pole of a convex mirror of focal lenght 15 cm. Find the nature and position of the image.​

Answer 1

Answer:

It is to be remembered that a convex mirror always forms the virtual, erect and diminished image. Given: Object distance,      Focal length, To find: Image distance, From mirror formula : Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification Hence it will be erect and diminished.

Explanation:

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Answer 2

Answer:

Given that,

Object distance, u = –10 cm (By using Cartesian sign convention)

Focal length of a convex mirror, f = + 15 cm (By sign convention)

1/f = 1/u + 1/v

$= > \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \\ = > \frac{1}{v} = \frac{1}{15} - \frac{1}{ - 10} \\ = > v = \frac{150}{25} = 6 \: cm.$

Positive sign indicates that the image is virtual.

Magnification = –v/u = –6/–10 = 0.6

Since ‘m’is positive and less than one, the image is erect and diminished.

An erect, virtual, and diminished image is formed at 6 cm from the pole, behind the mirror.