Question

Physics Question!

Q. There's a relation between the 1st equation of motion and the 3rd equation of motion. Explain with the help of a graph or the equation itself.

1. v=u+at
3. v^2-u^2=2as

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Answer 1

Answer:

The third equation is s = ut+ (1/2)at^2. So if you know u, a and t, use the first equation. If you know s, a and u (like for this)

Answer 2

Explanation:

distance traveled=area of trapezium OABC

S=1/2(sum of parallel side)× (height)

S=1/2 × (OA × BC)× OC

S=1/2) ( u+v) (t)

hence, v=u+at

t=v-u/a

S=1/2 u+v (v-u/a)

2as=(v+u)(v-u)

or, v^2-u^2