Physics Question
Topic:- Relative permittivity.
Two identical charged spheres are suspended by strings of equal length. The strings make an angle of 60° with each other . When suspended in a liquid of density 0.5g/cc. The angle remains the same. The dielectric constant of the liquid is? [density of the material of the sphere is1.5g/cc]
Answer with step by step process.
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Answered by
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Hello!!
let, in vacuum figure (1)
θ = 30°
Tsinθ = Fo
Tcosθ = mg
Fo = Force in a vacuum
dividing both we get,
In Liquid, figure(2)
θ= 30°
T'Sinθ = Fm
T'Cosθ = mg - U
Fm = Force in a liquid medium.
U = upthrust force applied by water on the sphere.
Divide both,
equating Eq.(1) and Eq.(2)
fo/fm = Er
dielectric constant [ Er ] = 1.5
Thanks!!
₳₳
let, in vacuum figure (1)
θ = 30°
Tsinθ = Fo
Tcosθ = mg
Fo = Force in a vacuum
dividing both we get,
In Liquid, figure(2)
θ= 30°
T'Sinθ = Fm
T'Cosθ = mg - U
Fm = Force in a liquid medium.
U = upthrust force applied by water on the sphere.
Divide both,
equating Eq.(1) and Eq.(2)
fo/fm = Er
dielectric constant [ Er ] = 1.5
Thanks!!
₳₳
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Answered by
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Answer:
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