PHYSICS
Two semicircular rings of linear mass
densities #(lambda) and 2#(lambda), and of radius 'R' each
are joined to form a complete ring. The
distance of the center of the mass of
complete ring from its centre is
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Explanation:
we know that center of mass of semi circular ring is 2r/pi
so, com of first one is 0, 2r1/pi
so,center of second one is 0,2r2/pi
we can form complete ring only if one is below other
after forming let center be 0,0
lamda1=2lamda2
m1/pir1^2=2m2/pir2^2
m1=2m2(r1/r2)^2
com of truncated bodies is
m1x1+m2x2 / m1+m2
and m1y1+m2y2 / m1+m2
Xcom=0
Ycom=m1(2r1/pi) -m2(2r2/pi) / m1+m2
m2(r1/r2)^2(2r1/pi)-m2(2r2/pi)/m1+m2
since r1=r2 and m1=2m2=m
Ycom=m1y1+m2y2/m1+m2
m(2r/pi)-m/2(2r/pi)/3m
2r/pi(m/2)/3m
r/3pi
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