Math, asked by SatwikSahu, 4 months ago

PIC
Factors of aPb2+ cd2 - a²c2-b²d2 are
(1) (a + d)(a - d)(b + c)(b - c) (2) (a2-b2)
Factors of 8x3 + 27v3 are​

Answers

Answered by umeshkumar703
1

Answer:

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Step-by-step explanation:

Given : (a²−b²)(c²−d²)−4abcd

=a²c²−a²d²−b²c²+b²d²−2abcd−2abcd

=a²c²+b²d²−2abcd−a²d²+b²c²−2abcd

=(ac−bd)²−(ad−bc)²

=(ac−bd−ad+bc)(ac−bd+ad−bc) ....Since [p²−q²=(p−q)(p+q)]

Answered by kamblesushma816
1

Answer:

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